Deep Learning & AI · Optoelectronics · Materials Analysis · Semiconductor Physics
LeetCode: [131] 分割回文串
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class Solution(): def isPdString(self, s): return s == s[::-1] def partition(self, s): res = [] self.backtrack(s, res, []) return res def backtrack(self, s, res, path): if not s: res.append(path) return for i in range(1, len(s) + 1): if self.isPdString(s[:i]): self.backtrack(s[i:], res, path + [s[:i]])
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