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| class Solution:
def topKFrequent(self, words, k):
words_dict = {}
for word in words:
if word not in words_dict.keys():
words_dict[word] = 1
else:
words_dict[word] += 1
words_dict = sorted(
words_dict.items(), key=lambda item: (-item[1], item[0]), reverse=True
)
words_dict.reverse()
words_dict = words_dict[:k]
return [i[0] for i in words_dict]
|
